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i need a statistics wizard...?
i was playing poker online and i was dealt 2 aces and two kings from one deck playing omaha and in another deck i was dealt an ace and a king playing hold em. what are the odds of having all six cards all being at least a king?????
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- It is 8/52 x 7/51 x 6/50 x 5/49 x 8/52 x 7/51 = approx. 0.0000054 or about 1 in 185,000. Perhaps not the 1 in millions that you expected.
- Assuming these are two full 52 card decks, Omaha: odds of the first card being ace or king is 8/52 given that it is, the odds of the second card being ace or king is 7/51 (there are 7 remaining aces/kings out of 51 remaining cards) given that it is, the odds of the second card being ace or king is 6/50 given that it is, the odds of the second card being ace or king is 5/49 multiply those together 8/52 x 7/51 x 6/50 x 5/49 Hold'em: odds of the first card being ace or king is 8/52 given that it is, odds of the second card being ace or king is 7/51 multiply thse together, 8/52 x 7/51 then multiply the two results, to get the odds of both events occurring. I don't feel like doing the calculations right now but there you go
- I'm not sure of the rules, did you play with 32 or 52 cards? Also, you don't say if you changed cards or if they came from the beginning. Assuming that you played 52 cards and got all without changing, you can calculate it like this: There are 4 Kings and 4 Aces in a 52 cards deck. So the chance for your first card being at least a king is 8/52. Now you have 51 cards left in the heap, with 7 being king or ace. So the chance for the second one is 7/51, For it to happen simultaneously, you have to multiply both probabilities. So for the first game you have (8/52)*(7/51)*(6/50)*(5/49) = 0.00026 or 4/100 of a percent. For the second game, it is (8/52)*(7/51) = 0.021. For both to happen, you have to multiply 0.00026*0.021 = 0.00005 or one chance in 200 000. If you played with 32 cards, you had one chance in 10 000. If you had those after exchanging bad cards, matters get more complicated and I can't give you a calculation without knowing the details.
